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convergence of random variables

1. types of convergence

2. law of large numbers

The difference between the strong and weak law of large numbers comes from the difference between convergence almost surely and convergence in probability.

3. continuous functions

If \(f\) is a continuous function then, if \(Y_n\) converges to \(Y\) (a.s. OR in probability OR in distribution) then \(f(Y_n)\) converges to \(f(Y)\)

4. marginal convergence

If \(X_n\) converges (a.s. OR in probability) and \(Y_n\) converges (a.s. OR in probability) then \((X_n, Y_n)\) converges to (X, Y)

BUT: \(X_n \overset{d}{\rightarrow} X\) and \(Y_n \overset{d}{\rightarrow} Y\) do not imply \((X_n, Y_n) \overset{d}{\rightarrow} (X, Y)\)

4.0.1. example

Let \(X_1 = X_2 = \cdots = X_n\) where \(X_1 \sim \mathcal{N}(0,1)\) and \(X\) is an independent Gaussian \(\mathcal{N}(0,1)\). We see that the \(X_n\) 's converge in distribution to \(X\), because they both have the same distribution

Let \(Y_1 = -X_1 = Y_2 = \cdots = Y_n\) where \(Y_1 \sim \mathcal{N}(0,1)\) and \(Y\) is an independent Gaussian \(\mathcal{N}(0,1)\). Similarly, the \(Y_n\) 's converge to \(Y\).

But for \((X_n, Y_n)\), \(X_n + Y_n = 0\) but \(X+Y \sim \mathcal{N}(0,2)\).

5. Slutsky's theorem

If \(X_n \overset{d}{\rightarrow} X\) and \(Y_n \overset{d}{\rightarrow} c\) for some constant \(c\). Then, \((X_n, Y_n) \overset{d}{\rightarrow} (X, c)\)

5.1. consequences

  • \(X_n + Y_n\) converges in distribution to \(X+c\)
  • \(X_nY_n\) converges in distribution to \(Xc\)

6. useful links

Created: 2024-07-15 Mon 01:28